5d^2+9d-7=0

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Solution for 5d^2+9d-7=0 equation: 



5d^2+9d-7=0

a = 5; b = 9; c = -7;
Δ = b2-4ac
Δ = 92-4·5·(-7)
Δ = 221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{221}}{2*5}=\frac{-9-\sqrt{221}}{10}
$


$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{221}}{2*5}=\frac{-9+\sqrt{221}}{10}
$

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